# In a Camp 95 Men had Provisions for 200 Days. After 5 Days 30 Men Left the Camp. For How Many Days will the Remaining Food Last Now?

### Computer MCQs Series for PPSC, FPSC – Most Repeated MCQs | Set 6

• In a camp 95 men had provisions for 200 days.
• After 5 days 30 men left the camp.
• Total days the remaining food would last can be figure out in this way.

## Explanation

Two given entities here are

• Men
• Days

To determine the relation here, let suppose; total days the remaining food would last = y

Case

95 men had provisions for 195 days.

After 5 days 30 men left the camp so remaining men = 95 – 30 = 65 men

Men           Days

95               195

65                 y

• More men mean less days.
• Less men mean more days.

This clearly indicates that there is inverse relation.

Direct/Indirect relation tells how the equation will be written.

95 : 65  ::  y : 195 ________ (i)

65 x y = 195 x 95 ________ (A)

After simplifying equation (A), we can easily figure out the value of y (y = 285 days)

## To Find

Total days the remaining food would last = ?

## Solution

### Method I

Let suppose

Total days the remaining food would last = y

Men           Days

95               195

65                 y

• Relation between men and days is inverse.

So

95 : 65  ::  y : 195

65 x y = 195 x 95

65y = 18525

y = 18525/65

y = 285 days

Total days the remaining food would last = 285 days

### Method II

Total provisions = 95 x 200

Total provisions = 19000

5 days provisions = 95 x 5

5 days provisions = 475

Remaining provisions = 19000 – 475

Remaining provisions = 18525

After 5 days 30 men left the camp

Remaining men = 95 – 30

Remaining men = 65 men

Total days the food would last = 18525/65

Total days the food would last = 285 days

## Conclusion

In a camp 95 men had provisions for 200 days. After 5 days 30 men left the camp. For 285 days the remaining food would last.