# Find a Positive Number Which When Increased by 17 is Equal to 60 Times the Reciprocal of the Number?

### Computer MCQs Series for PPSC, FPSC – Most Repeated MCQs | Set 6

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## Explanation

• Find a positive number which when increased by 17.
• Is equal to 60 times the reciprocal of the number.
• The number can be figure out in this way.

Let suppose the positive number is y.

60 times the reciprocal of the number

60 x 1/y

Positive number when increased by 17

y + 17 = 60 x 1/y ________ (i)

Through equation (i) we can easily find out the value of y (y = 3).

Number = ?

## Solution

Let suppose

Number = y

According to the given condition

y + 17 = 1/y x 60

y(y + 17) = 60

y2 + 17y = 60

y2 + 17y – 60 = 0

y2 + 20y – 3y – 60 = 0

y(y + 20) – 3(y + 20) = 0

(y + 20)(y – 3) = 0

y + 20 = 0           &                y – 3 = 0

y = -20 (not possible)           &                y = 3 (possible)

## Conclusion

Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number. The number is 3 which is the required answer.