# A Train 150 Meter Long Passes a km Stone in 15 Seconds and Another Train of the Same Length Travelling in Opposite Direction in 8 Seconds. The Speed of the Second Train is?

### Computer MCQs Series for PPSC, FPSC – Most Repeated MCQs | Set 6

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## Explanation

“A train 150 meter long passes a km stone in 15 seconds”; through this statement, the speed of first train will be calculated

Speed of first train = 150/15 = 10 m/sec

Assuming the speed of other train “y”, relative speed becomes y + 10. Total length becomes 300 m, time is also given i.e. 8 seconds. So, speed of other train will be determined with speed distance formula.

Speed = Distance/Time

## To Find

Speed of other train = ?

## Solution

Let suppose the speed of other train = y

The speed of first train = 150/15 = 10 m/sec

Relative speed = 10 + y

Total length = 150 + 150 = 300 meter

Time (Given) = 8 seconds

Now,

Speed = Distance/Time

10 + y = 300/8

y = 37.5 – 10

y = 27.5 m/sec

This speed in km/h will be

y = (27.5 x 3600)/1000

### Conclusion

A train 150 meter long passes a km stone in 15 seconds and another train of the same length travelling in opposite direction in 8 seconds. The speed of the second train will be 99km/h.