# 15 Men Take 21 Days of 8 Hours Each to Do a Piece of Work. How Many Days of 6 Hours Each would 21 Women Take if 3 Women do as Much Work as 2 Men?

### Computer MCQs Series for PPSC, FPSC – Most Repeated MCQs | Set 6

• 15 men take 21 days of 8 hours each to do a piece of work.
• 3 women do as much work as 2 men.
• Days required by the 21 women if each works for 6 hours can be figure out in this way.

## Explanation

Three given entities here are

• Women
• Hours
• Days

To determine the relation here, let suppose; Days required by the 21 women if each works for 6 hours = y

Case I

As

2 men = 3 women

1 men = 3/2 women

15 men = (3 x 15)/2

15 men = 45/2

15 men = 22.5 women

Women      Days

22.5            21

21             y

• More women mean less days.
• Less women mean more days.

This clearly indicates that there is direct relation.

Direct/Indirect relation tells how the equation will be written.

21 : 22.5  ::  21 : y ________ (i)

Case II

Hours         Days

8                 21

6                 y

• More hours mean less days.
• Less hours mean more days.

This clearly indicates that there is inverse relation.

Direct/Indirect relation tells how the equation will be written.

6 : 8  ::  21 : y ________ (ii)

By (i) and (ii)

21 : 22.5  ::  21 : y

6 : 8

21 x 6 x y = 22.5 x 8 x 21 ________ (A)

After simplifying equation (A), we can easily figure out the value of y (y = 30 days)

## To Find

Days required by the 21 women if each works for 6 hours = ?

## Solution

### Method I

Let suppose

Days required by the 21 women if each works for 6 hours = y

Women      Hours         Days

22.5            8                 21

21             6                 y

• Relation between women and days is inverse.
• Relation between hours and days is also inverse.

So

21 : 22.5  ::  21 : y

6 : 8

21 x 6 x y = 22.5 x 8 x 21

126y = 3780

y = 3780/126

y = 30 days

Days required by the 21 women if each works for 6 hours = 30 days

### Method II

As

2 men = 3 women

1 men = 3/2 women

15 men = (3 x 15)/2

15 men = 45/2

15 men = 22.5 women

Days required by the 22.5 women if each works for 8 hours = 21 days

Days required by the 22.5 women if each works for 1 hour = (21 x 8) days

Days required by the 22.5 women if each works for 1 hour = 168 days

Days required by the 1 woman if she works for 1 hour = (168 x 22.5) days

Days required by the 1 woman if she works for 1 hour = 3780 days

Days required by the 21 woman if each works for 1 hour = 3780/21 days

Days required by the 21 woman if each works for 1 hour = 180 days

Days required by the 21 woman if each works for 6 hours = 180/6 days

Days required by the 21 woman if each works for 6 hours = 30 days

Days required by the 21 women if each works for 6 hours = 30 days

## Conclusion

15 men take 21 days of 8 hours each to do a piece of work. 30 days of 6 hours each would 21 women take if 3 women do as much work ass 2 men.